How do you solve $x - 2 y = - 6$ $x - 2y = -6$ and $- x + y = 2$ $-x + y = 2$ ?

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How do you solve $x - 2 y = - 6$ $x - 2y = -6$ and $- x + y = 2$ $-x + y = 2$ ?

3 Answers

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Answer 1 · 2017-06-09T18:20:49

I got:
$x = 2$ $x=2$
$y = 4$ $y=4$

Explanation:

Have a look:

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Answer 2 · 2017-06-09T19:25:29

$x = 2 and y = 4$ $x=2 and y=4$

Explanation:

Make $x$ $x$ the subject of both equations:

$x = 2 y - 6 and x = y - 2$ $x= 2y-6" and "x= y-2$

The value of $x$ $x$ is the same, so if:

$x = x$ $" "x = x$ then:
$2 y - 6 = y - 2 \leftarrow$ $2y-6 = y-2" "larr$ solve for $y$ $y$

$2 y - y = - 2 + 6$ $2y-y= -2+6$

$y = 4$ $y =4$

$x = 2 (4) - 6$ $x = 2(4) -6$

$x = 8 - 6$ $x=8-6$

$x = 2$ $x=2$

Answer 3 · 2017-06-09T19:35:36

$x = 2$ $x=2$
$y = 4$ $y=4$

Explanation:

We could also solve this problem using substitution.

Solve the 1st equation for $x$ $x$ :

$x - 2 y = - 6$ $x-2y=-6$

$x = 2 y - 6$ $x=2y-6$

Substitute the above into the 2nd equation and solve for $y$ $y$ :

$- x + y = 2$ $-x+y=2$

$- (2 y - 6) + y = 2$ $-(2y-6)+y=2$

$- 2 y + 6 + y = 2$ $-2y+6+y=2$

$- y = - 4$ $-y=-4$

$y = 4$ $y=4$

Substitute $y$ $y$ into the 1st equation and solve for $x$ $x$ :

$x - 2 y = - 6$ $x-2y=-6$

$x - 2 (4) = - 6$ $x-2(4)=-6$

$x = 2$ $x=2$

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How do you solve $x - 2 y = - 6$ $x - 2y = -6$ and $- x + y = 2$ $-x + y = 2$ ?

3 Answers

Explanation:

Explanation:

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How do you solve x−2y=−6x - 2y = -6 and −x+y=2-x + y = 2?

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How do you solve $x - 2 y = - 6$ $x - 2y = -6$ and $- x + y = 2$ $-x + y = 2$ ?