How do you solve $\frac{x}{3} + 1 = 9$ $x/3+1=9$ ?

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Answer 1 · 2015-07-09T19:59:06

The answer is $x = 24$ $x=24$

$\frac{x}{3} + 1 = 9$ $x/3+1=9$

Multiply both sides times $3$ $3$ .

$x + 3 = 27$ $x+3=27$

Subtract 3 from both sides.

$x = 27 - 3$ $x=27-3$ =

$x = 24$ $x=24$

Answer 2 · 2015-07-09T20:06:28

$x \in {24}$ $x \in {24}$

Sum -1:

$\frac{x}{3} = 9 - 1$ $x/3 = 9 - 1$

Multiply by 3:

$x = (9 - 1) \cdot 3$ $x = (9 - 1) * 3$

How do you solve x3+1=9x/3+1=9?