How do you solve $x/3 - 2/3 = 1/x$ ?

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Answer 1 · 2015-05-27T03:18:56

$x/3 - 2/3 = 1/x$

$(x-2)/3 = 1/x$

cross multiplying:
$x(x-2) = 1.3$
$x^2 - 2x = 3$
$x^2 - 2x - 3 = 0$

Factorising the term to find solutions:

Splitting the middle term:
$x^2 - 3x + x - 3 = 0$
$x(x- 3) + 1(x - 3) = 0$

the solutions are $color(blue)(x = -1 , x=3$

How do you solve x/3 - 2/3 = 1/x x/3 - 2/3 = 1/x?