Question

How do you solve `x^3 - x^2 - 12x = 0`?

Answer 1

You can first factor out an x from each term to the left of the =.

Explanation:

`x(x^2 - x - 12) = 0`

Solve by factoring:

`x(x - 4)(x + 3) = 0`

`x = 0, 4 and -3`

Hopefully this helps.