How do you solve $x-(3x)/(2)=(x+7)/(x-11)$ ?

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Answer 1 · 2015-05-08T20:17:38

$x-(3x)/2 = (x+7)/(x-11)$

Simplify the left side of the equation:
$-x/2 = (x+7)/(x-11)$

Multiply both sides by $(-2)(x-11)$
$x^2-11x = -2x-14$

Re-arrange terms to the left side
$x^2-9x +14 = 0$

Factor
$(x-7)(x-2)=0$

State solutions:
$x=7$ or $x=2$

How do you solve x-(3x)/(2)=(x+7)/(x-11)x-(3x)/(2)=(x+7)/(x-11)?