How do you solve #x/4+9=x/2-4#?

1 Answer
Mar 4, 2018

See a solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(4)# to eliminate the fractions. #color(red)(4)# is used because it is the Lowest Common Denominator for both fractions:

#color(red)(4)(x/4 + 9) = color(red)(4)(x/2 - 4)#

#(color(red)(4) xx x/4) + (color(red)(4) xx 9) = (color(red)(4) xx x/2) - (color(red)(4) xx 4)#

#(color(red)(4)x)/4 + 36 = (color(red)(4)x)/2) - 16#

#color(red)(4)/4x + 36 = color(red)(4)/2x - 16#

#1x + 36 = 2x - 16#

Now, Subtract #color(red)(1x)# and add #color(blue)(16)# to each side of the equation to solve for #x# while keeping the equation balanced:

#1x - color(red)(1x) + 36 + color(blue)(16) = 2x - color(red)(1x) - 16 + color(blue)(16)#

#0 + 52 = (2 - color(red)(1))x - 0#

#52 = 1x#

#52 = x#

#x = 52#