How do you solve #x=4y# and #x=y-3 # using substitution?

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Answer 1 · 2016-03-16T13:16:20

#x,y=-4,-1#

#color(blue)(x=4y,x=y-3#

Substitute the value of #x# to the second equation

#rarr4y=y-3#

#rarr4y=y=-3#

#rarr3y=-3#

#rArrcolor(green)(y=-3/3=-1#

Substitute the value of #y# to the first equation

#rarrx=4(-1)#

#rArrcolor(green)(x=-4#

#:.color(green)(|bar (ul(x,y=-4,-1)))|#