How do you solve #(x+5)/(x-4)<=0#?

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Answer 1 · 2018-06-10T17:24:14

#[-5,4)#

Two equations can be formed from this:

#x+5<=0#
and
#x-4<=0#

Solve both to get

#x<=-5# and #x<=4#

however when #x=4# denominator is 0, and so makes the equation undefined, so #x<4#

so the two ranges are

#-5<=x<4# also written as #[-5,4)#