How do you solve $x - 5 y = 15$ $x-5y=15$ and $4 x - 3 y = 26$ $4x-3y=26$ using substitution?

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How do you solve $x - 5 y = 15$ $x-5y=15$ and $4 x - 3 y = 26$ $4x-3y=26$ using substitution?

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Answer 1 · 2015-02-05T20:11:57

you can isolate $x$ $x$ from the first equation giving:
$x = 5 y + 15$ $x=5y+15$ and substitute in the second:
$4 (5 y + 15) - 3 y = 26$ $4(5y+15)-3y=26$
$20 y + 60 - 3 y = 26$ $20y+60-3y=26$
$17 y = - 34$ $17y=-34$
$y = - 2$ $y=-2$

Substituting back in: $x = 5 y + 15$ $x=5y+15$ it gives you:
$x = - 10 + 15 = 5$ $x=-10+15=5$

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How do you solve $x - 5 y = 15$ $x-5y=15$ and $4 x - 3 y = 26$ $4x-3y=26$ using substitution?

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Science

Math

Humanities

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How do you solve x-5y=15x−5y=15x-5y=15 and 4x-3y=264x−3y=264x-3y=26 using substitution?

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How do you solve $x - 5 y = 15$ $x-5y=15$ and $4 x - 3 y = 26$ $4x-3y=26$ using substitution?