How do you solve #x-5y=15# and #4x-3y=26# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer GiĆ³ Feb 5, 2015 you can isolate #x# from the first equation giving: #x=5y+15# and substitute in the second: #4(5y+15)-3y=26# #20y+60-3y=26# #17y=-34# #y=-2# Substituting back in: #x=5y+15# it gives you: #x=-10+15=5# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 4219 views around the world You can reuse this answer Creative Commons License