How do you solve $x - 5 y = 6$ $x-5y=6$ , $2 x + 3 y = 12$ $2x+3y=12$ using substitution?

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Answer 1 · 2018-03-02T02:31:35

$x = 6$ $x=6$
$y = 0$ $y=0$

$x = 5 y + 6$ $x=5y+6$

$2 (5 y + 6) + 3 y = 12$ $2(5y+6)+3y=12$

$10 y + 12 + 3 y = 12$ $10y+12+3y=12$

$13 y + 12 = 12$ $13y+12=12$

$13 y = 0$ $13y=0$

$y = 0$ $y=0$

$x - 5 (0) = 6$ $x-5(0)=6$

$x = 6$ $x=6$

By the way, here's what the graph would kind of look like:
graph{(y)^2-(x-6)^2=0 [-5, 10, -5, 5]} If you don't get it then just ignore it.

How do you solve x−5y=6x-5y=6, 2x+3y=122x+3y=12 using substitution?