How do you solve x-6y=31x6y=31 and 6x+9y=-846x+9y=84 using matrices?

1 Answer
Sep 30, 2016

(x,y)=color(green)(-5,-6)(x,y)=5,6

Explanation:

Given the equations:
color(white)("XXX")x-6y=31XXXx6y=31
color(white)("XXX")6x+9y=-84XXX6x+9y=84

We can write these in "augmented matrix form as:)
color(white)("XXX")( (1,-6,31),(6,9,-84) )

This can be solved using the normal operations we would perform on the original equations (with the variables and equal side "assumed").

color(red)("Alternately, we can use Cramer's Rule with Matrix Determinants")

color(white)("XXX")color(blue)("Although I demonstrate the soloution (below) using hand calculations")
color(white)("XXX")color(blue)("the power of the Matrix Methods lies in their compatibility with")
color(white)("XXX")color(blue)("computer systems. For example, the evaluation of Determinants")
color(white)("XXX")color(blue)("is a build-in function for most spreadsheets.")

If M_(xy)=((1,-6),(6,9))color(white)("XX")M_(cy)=((31,-6),(-84,9))color(white)("XX")M_(xc)=((1,31),(6,-84))

x=(|M_(cy)|)/(|M_(xy)|)" and " y=(|M_xc|)/(|M_(xy)|)

Where the Determinants:
color(white)("XXX")|M_(xy)|= 1xx9-6xx(-6)= 9+36=45

color(white)("XXX")|M_(cy)|= 31xx9-(-84)xx(-6))=279-504=-255

color(white)("XXX")|M_(xc)|=1xx(-84)-6xx31=-84-186=-270

Giving
color(white)("XXX")x=-255/45=-6
and
color(white)("XXX")y=-270/45=-5