How do you solve x−9y=−80 and 2y−2x=16 using substitution?
1 Answer
May 27, 2018
Explanation:
x−9y=−80→(1)
2y−2x=16→(2)
rearrange equation (1) expressing x in terms of y
x=−80+9y→(3)
substitute x=−80+9y in equation (2)
2y−2(−80+9y)=16
2y+160−18y=16
−16y+160=16
subtract 160 from both sides
−16y=16−160=−144
divide both sides by −16
y=−144−16=9
substitute y=9 in equation (3)
x=−80+81=1
solution is (x,y)→(1,9)
graph{(y-1/9x-80/9)(y-x-8)=0 [-20, 20, -10, 10]}