How do you solve x9y=80 and 2y2x=16 using substitution?

1 Answer
May 27, 2018

(x,y)(1,9)

Explanation:

x9y=80(1)

2y2x=16(2)

rearrange equation (1) expressing x in terms of y

x=80+9y(3)

substitute x=80+9y in equation (2)

2y2(80+9y)=16

2y+16018y=16

16y+160=16

subtract 160 from both sides

16y=16160=144

divide both sides by 16

y=14416=9

substitute y=9 in equation (3)

x=80+81=1

solution is (x,y)(1,9)
graph{(y-1/9x-80/9)(y-x-8)=0 [-20, 20, -10, 10]}