How do you solve #x - y = 16# and #2x + y = 2#?

Question

1974 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-02T14:11:35

The solution for the system of equations is
#color(blue)(x=6, y=-10#

#x−color(blue)(y)=16 #.....equation #(1)#
#2x+color(blue)(y)=2#.....equation #(2)#

Upon adding the two equations #color(blue)(y# gets eliminated.

#x−cancelcolor(blue)(y)=16 #
#2x+cancelcolor(blue)(y)=2#

#3x=18#
#color(blue)(x=6#

Now, we substitute the value of #x# to find #y#
From equation #1#:

#x−y=16 #

#x−16=y #

#y=6-16#
#color(blue)(y=-10#