How do you solve x+y = 4x+y=4 and 5x-2y = -15x2y=1?

1 Answer
Jun 1, 2015

Starting with x+y=4x+y=4, subtract xx from both sides to get:

y = 4-xy=4x

Then substitute this in the second equation as follows:

-1 = 5x-2y1=5x2y

= 5x-2(4-x) = 5x-8+2x = 7x-8=5x2(4x)=5x8+2x=7x8

Add 88 to both ends to get:

7x = 77x=7

Divide both sides by 77 to get

x = 1x=1

Substitute that value for xx into y = 4-xy=4x to get

y=4-x=4-1=3y=4x=41=3