How do you solve x+y=6 and x-y=2? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Veddesh #phi# Mar 27, 2016 #(x,y)=(4,2)# Explanation: #color(blue)(x+y=6# #color(blue)(x-y=2# We can get rid of #y# in the first equation by #-y# in the second equation. #:.# Add the equations #rarr(x+y=6)+(x-y=2)# #rarr2x=8# #rArrcolor(green)(x=8/2=4# Substitute the value of #x# to the first equation #rarr4+y=6# #rarry=6-4# #rArrcolor(green)(y=2# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 6707 views around the world You can reuse this answer Creative Commons License