How do you solve $x y - 3 x = 40$ $xy - 3x = 40$ ; $x = 5$ $x= 5$ ?

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Answer 1 · 2018-06-09T12:31:21

$y = 11$ $y =11$

$x y - 3 x = 40$ $xy - 3x = 40$ ----- equation (1)

Given $x = 5$ $x = 5$

Substituting the value of $x$ $x$ in equation (1):

$5 \times y - 3 \times 5 = 40$ $5 xx y - 3 xx 5 = 40$

$\Rightarrow 5 y - 15 = 40$ $=> 5y - 15 = 40$

$\Rightarrow 5 y = 40 + 15 = 55$ $=> 5y = 40 +15 = 55$

$\Rightarrow 5 y = 55$ $=> 5y =55$

$\Rightarrow y = \frac{55}{5}$ $=> y = 55/5$

$therefore y = 11$

How do you solve xy - 3x = 40xy−3x=40xy - 3x = 40; x= 5x=5x= 5?