How do you solve $y = \frac{1}{2} x + 4$ $y=1/2x+4$ and $y = - 4 x - 5$ $y=-4x-5$ using substitution?

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How do you solve $y = \frac{1}{2} x + 4$ $y=1/2x+4$ and $y = - 4 x - 5$ $y=-4x-5$ using substitution?

1 Answer

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Answer 1 · 2016-07-21T21:58:13

$x = - 2$ $x =-2$
$y = 3$ $y=3$

Explanation:

$y = \frac{x}{2} + 4 and y = - 4 x - 5$ $y=x/2+4 and y=-4x-5$
so
$\frac{x}{2} + 4 = - 4 x - 5$ $x/2+4=-4x-5$
or
$4 x + \frac{x}{2} = - 5 - 4$ $4x+x/2=-5-4$
or
$9 \frac{x}{2} = - 9$ $9x/2=-9$
or
$x = - 2$ $x =-2$
Substituting the value of x in the equation $y = \frac{x}{2} + 4$ $y=x/2+4$
we get
$y = - \frac{2}{2} + 4$ $y=-(2)/2+4$ = $3$ $3$

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How do you solve $y = \frac{1}{2} x + 4$ $y=1/2x+4$ and $y = - 4 x - 5$ $y=-4x-5$ using substitution?

1 Answer

Explanation:

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How do you solve $y = \frac{1}{2} x + 4$ $y=1/2x+4$ and $y = - 4 x - 5$ $y=-4x-5$ using substitution?