How do you solve # (y-1)/(y-2)=-y/(y+1)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Konstantinos Michailidis Oct 2, 2015 Refer to explanation Explanation: We multiply both sides with #(y-2)*(y+1)# hence we get #(y-1)/(y-2)=-y/(y+1)=>(y+1)*(y-1)=-(y-2)*y=>y^2-1=-y^2+2y=> 2y^2+2y-1=0=>y_1=-1/2-sqrt3/2 or y_2=-1/2+sqrt3/2# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1405 views around the world You can reuse this answer Creative Commons License