How do you solve #y=(16-6)/2#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer LM Dec 8, 2016 #y = 5# Explanation: #y = (16-6)/2# this needs to be simplified: #(16-6)/2 = 10/2 = 5# #y = (16-6)/2 = 10/2 = 5# #y = 5# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1949 views around the world You can reuse this answer Creative Commons License