How do you solve $y= 3x+8$ and $y=5x-10$ using substitution?

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Answer 1 · 2016-03-09T13:56:07

The solution for the system of equations is:
$color(green)(x=9$
$color(green)(y=35$

$color(blue)(y=3x+8$ .....equation $(1)$

$y=5x−10$ ....equation $(2)$

Solving by substitution:
Substituting equation $(1)$ in $(2):$

$y=5x−10$

$color(blue)(3x+8)=5x−10$

$8+10=5x -3x$

$18=2x$

$x=18/2$

$color(green)(x=9$

Finding $y$ from equation $(1):$
$y=3x+8$

$y=3 xx 9+8$

$y=27+8$

$color(green)(y=35$

How do you solve y= 3x+8y= 3x+8 and y=5x-10y=5x-10 using substitution?