How do you solve $y=4/x$ and $y=3x-1$ using substitution?

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Answer 1 · 2016-07-01T16:18:10

$x=4/3$ or $x=-1$

To solve $y=4/x$ and $y=3x-1$ using substitution, just substitute value of $y$ from first equation into second, which leads to

$4/x=3x-1$ or multiplying each by $x$ (we assome $x!=0$ , we get

$4=3x^2-x$ or

$3x^2-x-4=0$ or

$3x^2+3x-4x-4=0$ or

$3x(x+1)-4(x+1)=0$ or

$(3x-4)(x+1)=0$ , which means that $3x-4=0$ or $x+1=0$

i.e. $x=4/3$ or $x=-1$

How do you solve y=4/x y=4/x and y=3x-1 y=3x-1 using substitution?