How do you solve $y = 5 - x$ $y=5-x$ and $1 = 4 x + 3 x$ $1=4x+3x$ using substitution?

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Answer 1 · 2017-01-25T13:13:59

$y = 4 \frac{6}{7}, x = \frac{1}{7}$ $y=4 6/7, x= 1/7$

$y = 5 - x, 1 = 4 x + 3 x$ $y=5-x,1=4x+3x$

$:.y=5-x$ ------(1)

$:.7x=1$

$x= 1/7$

substitute $x= 1/7$ in-----(1)

$:.y=5-(1/7)$

$:.y=35/7-1/7$

$:.y=34/7$

$:.y=4 6/7$

check:

substitute $y= 34/7, x=1/7$ in--------(1)

$:.34/7=35/7-1/7$

$:.34/7=34/7$

How do you solve y=5-xy=5−xy=5-x and 1=4x+3x1=4x+3x1=4x+3x using substitution?