How do you solve $y= x+3$ and $x-4y=0$ using substitution?

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Answer 1 · 2017-08-22T06:57:11

$x = -4$

$y = -1$

$y = x+3" "(1)$

$x-4y = 0" "(2)$

Substitute the value of $y$ in equation $(2)$ . We get

$x-4(x+3) = 0$

$x-4x-12 = 0$

$-3x = 12$

$x = -4$

Substitute the value in equation $(1)$ . We get

$y = -4+3$

$y = -1$

How do you solve y= x+3y= x+3 and x-4y=0 x-4y=0 using substitution?