How do you subtract $(4 - 6 d^{2}) - (9 d^{2} - 7)$ $(4- 6d ^ { 2} ) - ( 9d ^ { 2} - 7)$ ?

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How do you subtract $(4 - 6 d^{2}) - (9 d^{2} - 7)$ $(4- 6d ^ { 2} ) - ( 9d ^ { 2} - 7)$ ?

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Answer 1 · 2018-06-03T12:30:18

$11 - 15 d^{2}$ $11-15d^2$

Explanation:

$4 - 6 d^{2} - (9 d^{2} - 7) = 4 - 6 d^{2} - 9 d^{2} + 7 = 11 - 15 d^{2}$ $4-6d^2-(9d^2-7)=4-6d^2-9d^2+7=11-15d^2$

Answer 2 · 2018-06-03T12:37:18

$11 - 15 d^{2}$ $11-15d^2$

Explanation:

$distribute brackets and collect like terms$ $"distribute brackets and "color(blue)"collect like terms"$

$note that the second bracket is multiplied by - 1$ $"note that the second bracket is multiplied by "-1$

$1 (4 - 6 d^{2}) - 1 (9 d^{2} - 7)$ $1(4-6d^2)-1(9d^2-7)$

$= + 4 - 6 d^{2} - 9 d^{2} + 7$ $=color(red)(+4)color(blue)(-6d^2)color(blue)(-9d^2)color(red)(+7)$

$= 11 - 15 d^{2}$ $=11-15d^2$

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How do you subtract $(4 - 6 d^{2}) - (9 d^{2} - 7)$ $(4- 6d ^ { 2} ) - ( 9d ^ { 2} - 7)$ ?

2 Answers

Explanation:

Explanation:

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How do you subtract $(4 - 6 d^{2}) - (9 d^{2} - 7)$ $(4- 6d ^ { 2} ) - ( 9d ^ { 2} - 7)$ ?