How do you subtract #(5-2i)-(6+8i)#?

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Answer 1 · 2017-05-08T12:53:05

#5-2i-6-8i# In other words #-1-10i#

When you write down your equation in open form:

#5-2i-6-8i#

You can arrange the above equation

#5-6-2i-8i#

In other words,

#=-1-10i#

Thisis your answer

#-1-10i#