How do you subtract #\frac{2x}{x^2+10x+25}-\frac{3x}{2x^2+7x-15}#?

1 Answer
Dec 20, 2014

First, we're going to simplify the expressions a bit. We can do this by factoring both the denominators:
#x^2+10x+25 = (x+5)^2#

#2x^2+7x-15=(x+5)(2x-3)#

To substract two fractions with a different denominator, we will always have to find the LCM of the denominators. In this case it is #(x+5)^2(2x-3)# since this can evenly be divided by both the denominators.

Let's combine what we've got already:
#(2x)/(x+5)^2-(3x)/((x+5)(2x-3))#

Now for changing to the LCM:
#(2x-3)/(2x-3)*(2x)/(x+5)^2 - (x+5)/(x+5)(3x)/((x+5)(2x-3))#

#= (2x*(2x-3)-3x*(x+5))/((x+5)^2(2x-3))#

Distribute the terms:

#(4x^2-6x-3x^2-15x)/((x+5)^2(2x-3))#

#= (x^2-21x)/((x+5)^2(2x-3))#

You could've also done this without factoring, but it would've been way harder. Factoring always makes your life easier!

I really hope this helped.