How do you subtract #(x^2-8x+7)-(6x^2+7x-3)#?

1 Answer
Monica
Feb 5, 2015

You need to remember that the #-# is actually a #-1# in front of the second expression.

#(x^2-8x+7)-1(6x^2+7x-3)#

The first set of parentheses can drop since there is merely a 1 in front of them. You will need to distribute the #-1# to the second set of parentheses.

#x^2-8x+7-6x^2-7x+3#

Now you are ready to combine like terms. Remember that the sign in front of the term moves with the term.

#x^2-6x^2-8x-7x+7+3#

Giving me the following answer:

#-5x^2-15x+10#

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