How do you translate word phrases to algebraic expressions: a number squared plus two times the number less 7 is equal to zero?

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How do you translate word phrases to algebraic expressions: a number squared plus two times the number less 7 is equal to zero?

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Answer 1 · 2016-07-06T22:43:15

$x^{2} + 2 (x - 7) = 0$ $x^2 + 2(x-7) = 0$

Explanation:

Let's break this down.

a number: this means "any number", so we can substitute that with a variable, $x$ $x$

squared: this means squaring the number, or multiplying it by itself (written as $x^{2}$ $x^2$ ; $x$ $x$ squared)

two times the number: we've already established the number is $x$ $x$ , and two times that number would be $2 x$ $2x$ (since we are multiplying it by two, hence "times")

the number less 7: this looks like subtraction (a number less seven would be $x - 7$ $x - 7$

For the parts I left out, I thought they would be easy to comprehend. If you did not understand them, you will find out when I go through setting this up:

A number

$x$ $x$

squared

$x$ $x^$

plus two times the number less 7

$x^{2} + 2 (x - 7)$ $x^2 + 2(x-7)$

is equal to zero

$x^{2} + 2 (x - 7) = 0$ $x^2 + 2(x-7) = 0$

I believe this is what you meant.

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How do you translate word phrases to algebraic expressions: a number squared plus two times the number less 7 is equal to zero?

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