How do you use a graphing calculator to find the limit of the sequence $a_n=2^n/(2^n+1)$ ?

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Answer 1 · 2016-12-10T13:11:03

Plot it as a continuous function. As you are looking at end behaviour it does not matter that you are plotting it as 'every where dense'

$y=(2^x)/(2^x+1)$

Every where dense $->$ all values rather than just select values

Write as $a_n=(2^n)/(2^n(1+1/2^n)) = 1/(1+1/2^n)$

When $n=0" "$ then we have $" "a_0=1/2$

$lim_(n->+oo) a_n= 1/1=1$

$lim_(n->-oo) a_n=1/(1+oo) ->0$

Tony B

How do you use a graphing calculator to find the limit of the sequence a_n=2^n/(2^n+1)a_n=2^n/(2^n+1)?