How do you use $f (x)= 2x - 3$ and $g(x)= 1-x^2$ to evaluate f(g(0))?

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Answer 1 · 2017-01-12T01:35:35

See the full process for evaluating these functions below.

First, evaluate $g(0)$ :

If $g(color(red)(x)) = 1 - x^2$ , then

$g(color(red)(0)) = 1 - 0^2$

$g(color(red)(0)) = 1 - 0$

$g(0) = 1$

Second, evaluate $f(g(0))$ :

If $f(color(red)(x)) = 2x - 3$ and $g(0) = 1$ , then

$f(g(0)) = f(1)$

and

$f(color(red)(1)) = (2 xx 1) - 3$

$f(color(red)(1)) = 2 - 3$

$f(color(red)(1)) = -1$

Therefore

$f(g(0)) = -1$

How do you use f (x)= 2x - 3f (x)= 2x - 3 and g(x)= 1-x^2g(x)= 1-x^2 to evaluate f(g(0))?