How do you use Heron's formula to find the area of a triangle with sides of lengths #4 #, #4 #, and #5 #?
1 Answer
Jan 24, 2016
Explanation:
Heron's formula states that for a triangle with sides
#A=sqrt(s(s-a)(s-b)(s-c))#
Here, we know that
#s=(4+4+5)/2=13/2#
which gives an area of
#A=sqrt(13/2(13/2-4)(13/2-4)(13/2-5))#
#A=sqrt(13/2(5/2)(5/2)(3/2))#
#A=sqrt((39xx5^2)/4^2)#
#A=(5sqrt39)/4approx7.806#