How do you use implicit differentiation to find #(dy)/(dx)# given #3x^2y+2xy^3=1#?
1 Answer
Sep 15, 2016
Explanation:
differentiate with respect to x, using the
#color(blue)"product rule"#
#3x^2dy/dx+6xy+2x.3y^2dy/dx+2y^3=0#
#rArr3x^2dy/dx+6xy+6xy^2dy/dx+2y^3=0#
#rArrdy/dx(3x^2+6xy^2)=-2y^3-6xy#
#rArrdy/dx=(-2y^3-6xy)/(3x^2+6xy^2)#
