Question

How do you use implicit differentiation to find dy/dx given `(x^2+y^2)^99=alpha`?

Answer 1

`-x/y`

Explanation:

Given `f(x,y)=0`

`f_xdx+f_ydy=0` so `dy/dx=-f_x/f_y`

Here

`f_x = 198 x (x^2 + y^2)^98`
`f_y=198 y (x^2 + y^2)^98`

then

`dy/dx = -x/y`