How do you use implicit differentiation to find #(dy)/(dx)# given #xy=1#?
1 Answer
Sep 8, 2016
Explanation:
We have to use the
#color(blue)"product rule"# for xy and note that the derivative of a constant is zero.
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(d/dx(y)=dy/dx)color(white)(a/a)|)))# Differentiate with respect to x.
#rArrx.dy/dx+y.1=0rArrx.dy/dx=-yrArrdy/dx=-y/x#