How do you use long division to divide #(4x^3-7x^2-11x+5)div(4x+5)#?

Question

5386 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-09T13:31:17

The remainder is #=0# and the quotient is #=x^2-3x+1#

Let's do the long division

#color(white)(aaaa)##4x^3-7x^2-11x+5##color(white)(aaaa)##|##4x+5#

#color(white)(aaaa)##4x^3+5x^2##color(white)(aaaaaaaaaaaaa)##|##color(red)(x^2-3x+1)#

#color(white)(aaaaaa)##0-12x^2-11x#

#color(white)(aaaaaaaa)##-12x^2-15x#

#color(white)(aaaaaaaaaaa)##-0+4x+5#

#color(white)(aaaaaaaaaaaaaaa)##+4x+5#

#color(white)(aaaaaaaaaaaaaaaa)##+0+0#

The remainder is #=0# and the quotient is #=x^2-3x+1#