How do you use long division to divide $(4x^3-7x^2-11x+5)div(4x+5)$ ?

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Answer 1 · 2017-03-09T13:31:17

The remainder is $=0$ and the quotient is $=x^2-3x+1$

Let's do the long division

$color(white)(aaaa)$ $4x^3-7x^2-11x+5$ $color(white)(aaaa)$ $|$ $4x+5$

$color(white)(aaaa)$ $4x^3+5x^2$ $color(white)(aaaaaaaaaaaaa)$ $|$ $color(red)(x^2-3x+1)$

$color(white)(aaaaaa)$ $0-12x^2-11x$

$color(white)(aaaaaaaa)$ $-12x^2-15x$

$color(white)(aaaaaaaaaaa)$ $-0+4x+5$

$color(white)(aaaaaaaaaaaaaaa)$ $+4x+5$

$color(white)(aaaaaaaaaaaaaaaa)$ $+0+0$

The remainder is $=0$ and the quotient is $=x^2-3x+1$

How do you use long division to divide (4x^3-7x^2-11x+5)div(4x+5)(4x^3-7x^2-11x+5)div(4x+5)?