How do you use metric prefixes?

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How do you use metric prefixes?

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Answer 1 · 2017-06-10T13:45:28

Hopefully correctly.........

Explanation:

$m L$ $mL$ $=$ $=$ $10^{- 3} \cdot L$ $10^-3*L$ ;

$μ s$ $mus$ $=$ $=$ $10^{- 6} \cdot s$ $10^-6*s$ ;

$k m$ $km$ $=$ $=$ $10^{3} \cdot m$ $10^3*m$ .

A good illustration of this is the strict use of $d m^{3}$ $dm^3$ in preference to $litres$ $"litres"$ . Now $1 \cdot m^{3}$ $1*m^3$ is an absurdly large volume, and if you ever mix and lay $5 - 6 \cdot m^{3}$ $5-6*m^3$ of concrete that is a good day's hard work.

Back to the problem, $1 \cdot L \equiv 1 \cdot d m^{3}$ $1*L-=1*dm^3$ ; and $d = deci = 10^{- 1}$ $d="deci"=10^-1$ . And thus $1 \cdot d m^{3} \equiv {(1 \times 10^{- 1} \cdot m)}^{3} \equiv 10^{- 3} \cdot m^{3} \equiv \frac{1}{1000} \cdot m^{3}$ $1*dm^3-=(1xx10^-1*m)^3-=10^-3*m^3-=1/1000*m^3$ as required.

And so...............

$6.37xx10^-2*L=6.37xx10^-2*cancelLxx10^3*mL*cancel(L^-1)-=63.7*mL$

Agreed?

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How do you use metric prefixes?

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