How do you use polynomial synthetic division to divide $(x^3+8)div(x+2)$ and write the polynomial in the form $p(x)=d(x)q(x)+r(x)$ ?

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Answer 1 · 2017-07-21T16:30:01

$x^2-2x+4$

Let's use the formula :

$a^3+b^3=(a+b)(a^2-ab+b^2)$

$(x^3+8)/(x+2)=(x^3+2^3)/(x+2)=(cancel((x+2))(x^2-2x+4))/cancel(x+2)=$

$x^2-2x+4$

How do you use polynomial synthetic division to divide (x^3+8)div(x+2)(x^3+8)div(x+2) and write the polynomial in the form p(x)=d(x)q(x)+r(x)p(x)=d(x)q(x)+r(x)?