How do you use synthetic division to divide $(2x^3-x^2+5x-12) /(2x - 3)$ ?

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Answer 1 · 2018-03-28T11:46:28

Quotient is $x^2+x+4$ and remainder is $0$ .

$2x^3-x^2+5x-12$

= $2x^3-3x^2+2x^2-3x+8x-12$

= $x^2*(2x-3)+x*(2x-3)+4*(2x-3)$

= $(2x-3)*(x^2+x+4)$

Hence quotient is $x^2+x+4$ and remainder is $0$ .

How do you use synthetic division to divide (2x^3-x^2+5x-12) /(2x - 3) (2x^3-x^2+5x-12) /(2x - 3) ?