How do you use synthetic division to divide #4a^2 + 19a + 21# by #a+1#?

Question

1151 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-14T18:06:00

#4a^2 + 19a + 21# divided by #a+1#

#a+1=a-(-1)#

#"-1" ||# #"4 " " " "19 " " " "21 "#
#+# #"" " " " " "" "-4" " " " -15" "#
#"" " "##------#
#" "" "4" "15" "|6" "#

The quotient is #4a+15# and the remainder is #6#

We can check our answer by finding:

#(a+1)(4a+15) + 6#

#= 4a^2+15a+4a+15 + 6#

#= 4a^2+19a+21# which is the dividend.