How do you use synthetic division to divide $(x^{3} - 2 x - 22 x + 40)$ $(x^3-2x-22x+40)$ divided by (x-4)?

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Answer 1 · 2017-12-09T21:42:29

The quotient is $x^{2} + 4 x - 8 + \frac{8}{x - 4}$ $x^2+4x-8+\frac{8}{x-4}$ .

First, a quick overview of synthetic division:

![mathbitsnotebook.com]( useruploads.socratic.org )

In this problem, the number outside the L-shape will be $4$ $4$ .

The coefficients inside will be $1$ $1$ , $0$ $0$ , $- 24$ $-24$ , and $40$ $40$ .

The remainder will always be the last number to the right, divided by the entire original divisor.

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How do you use synthetic division to divide (x^3-2x-22x+40)(x3−2x−22x+40)(x^3-2x-22x+40) divided by (x-4)?