How do you use synthetic division to find the zeroes of f(x)=x43x39x23x10?

1 Answer
Jul 24, 2015

The zeroes of f(x)=x43x39x23x10 are 2,5,i,i.

Explanation:

According to the rational root theorem, the rational roots of f(x)=0 must all be of the form pq with p a divisor of 10 and q a divisor of 1.

So the only possible rational roots are ±1,±2,±5,±10.

We have to test all eight possibilities.

Here are the only two that work.

1

and

2

So 2 and 5 are zeroes of the polynomial.

That means that x+2 and x5 are factors, and

(x+2)(x5)=x23x10 is also a factor.

We can use synthetic division to find the other factor.

3

The other factor is x2+1.

x2+1=0
x2=1
x=±1=±i

x=i or x=i

So

f(x)=x43x39x23x10=(x+2)(x5)(x2+1).

and

The roots of f(x)=x43x39x23x10 are 2,5,i,i.