How do you use synthetic division to find x=-1 for $P(x)= x^3+2x^2-5x+6$ ?

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How do you use synthetic division to find x=-1 for $P(x)= x^3+2x^2-5x+6$ ?

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Answer 1 · 2017-06-06T14:48:24

The remainder is $=12$ and the quotient is $=x^2+x-6$

Explanation:

Let's perform the synthetic division

$color(white)(aaaa)$ $-1$ $color(white)(aaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaa)$ $2$ $color(white)(aaaaaa)$ $-5$ $color(white)(aaaaa)$ $6$
$color(white)(aaaaaaaaaaaa)$ _________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $color(white)(aaaaaa)$ $-1$ $color(white)(aaaaaa)$ $-1$ $color(white)(aaaaa)$ $6$
$color(white)(aaaaaaaaaaaa)$ ________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaaa)$ $1$ $color(white)(aaaaaa)$ $-6$ $color(white)(aaaa)$ $color(red)(12)$

The remainder is $=12$ and the quotient is $=x^2+x-6$

$(x^3+2x^2-5x+6)/(x+1)=x^2+x-6+12/(x+1)$

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How do you use synthetic division to find x=-1 for $P(x)= x^3+2x^2-5x+6$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you use synthetic division to find x=-1 for P(x)= x^3+2x^2-5x+6 P(x)= x^3+2x^2-5x+6 ?

1 Answer

Explanation:

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Impact of this question

How do you use synthetic division to find x=-1 for $P(x)= x^3+2x^2-5x+6$ ?