How do you use synthetic substitution to find x=4 for $p (x) = x^{3} - 4 x^{2} + 4 x - 5$ $p(x)=x^3-4x^2+4x-5$ ?

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How do you use synthetic substitution to find x=4 for $p (x) = x^{3} - 4 x^{2} + 4 x - 5$ $p(x)=x^3-4x^2+4x-5$ ?

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Answer 1 · 2015-09-06T02:01:26

p(4)=11

Explanation:

It is presumed it is required to know p(4). For this just amke x=4 and simplify to get p(4)=11. Now this means that if p(x) is divided by x-4, the remainder would be 11.

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How do you use synthetic substitution to find x=4 for $p (x) = x^{3} - 4 x^{2} + 4 x - 5$ $p(x)=x^3-4x^2+4x-5$ ?

1 Answer

Explanation:

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How do you use synthetic substitution to find x=4 for p(x)=x^3-4x^2+4x-5p(x)=x3−4x2+4x−5p(x)=x^3-4x^2+4x-5?

1 Answer

Explanation:

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How do you use synthetic substitution to find x=4 for $p (x) = x^{3} - 4 x^{2} + 4 x - 5$ $p(x)=x^3-4x^2+4x-5$ ?