Question

How do you use the chain rule to differentiate `1/-sinx`?

Answer 1

`f'(x) = cosx/sin^2x`

Explanation:

`f(x) = -1/sinx`

`f'(x) =-d/dx(sinx)^-1`

`= - (-1*(sinx)^-2) * d/dx sinx` (Power rule and chain rule)

`=(sinx)^-2 * cosx`

`= cosx/sin^2x`