Question

How do you use the chain rule to differentiate `cos(10csc10x)`?

Answer 1

`100sin(10csc(10x))csc(10x)cot(10x)`

Explanation:

`d/dx(cos(10csc(10x)))=-sin(10csc(10x))*d/dx(10csc(10x))` (chain rule)
`=-sin(10csc(10x))*10(-csc(10x)cot(10x))*d/dx(10x)` (chain rule again)

`=10sin(10csc(10x))*(csc(10x)cot(10x))*10`
`=100sin(10csc(10x))csc(10x)cot(10x)`