Question

How do you use the chain rule to differentiate `(ln4x)^100`?

Answer 1

`(100(ln4x)^99)/x`

Explanation:

`f(x) = (ln4x)^100`

Applying the power rule and chain rule

`f'(x) = 100* (ln4x)^99 * d/dxln4x`

`= 100* (ln4x)^99 * 1/(4x) * 4` [Standard differential and chain rule]

`=(100(ln4x)^99)/x`