Question

How do you use the chain rule to differentiate `y=2(x^3-x)^-2`?

Answer 1

`-4(x^3-x)^(-3)*(3x^2-1)`

Explanation:

`(dy)/dx=d/dx(2(x^3-x)^(-2))`

`(dy)/dx=-4(x^3-x)^(-3)*d/dx(x^3-x)` (chain rule)

`(dy)/dx=-4(x^3-x)^(-3)*(3x^2-1)`