How do you use the difference of two cubes formula to factor #x^6-y^3#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Don't Memorise May 2, 2015 #x^6 - y^3 = (x^2)^3 - y^3# The Difference of Cubes Formula says #color(blue)(a^3 - b^3 = (a-b)(a^2 +ab+b^2)# Hence #(x^2)^3 - y^3 = (x^2 - y)((x^2)^2 +x^2y +y^2)# # =color(green)( (x^2 - y)(x^4 +x^2y + y^2)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1728 views around the world You can reuse this answer Creative Commons License