Question

How do you use the difference of two squares formula to solve `4x^2=25`?

Answer 1

`f(x) = 4x^2 - 25 = (2x - 5)(2x + 5) = 0`

`(2x - 5) = 0 --> x = 5/2`

`(2x + 5) = 0 --> x = -5/2`