How do you use the distributive property to find 5 x 89?

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Answer 1 · 2018-03-14T13:36:11

$445$ $445$

$express 89 as 89 = (90 - 1)$ $"express 89 as "89=(90-1)$

$\Rightarrow 5 (90 - 1)$ $rArr5(90-1)$

$= 450 - 5$ $=450-5$

$= 445$ $=445$

Answer 2 · 2018-03-14T13:36:11

See a solution process below:

We can rewrite the number 89 as:

$89 = 80 + 9$ $89 = 80 + 9$

We then rewrite the expression in the problem as:

$5 \times (80 + 9)$ $5 xx (80 + 9)$ or $5 (80 + 9)$ $5(80 + 9)$

Using the distributive property we can rewrite and evaluate the expression as:

$(5 \times 80) + (5 \times 9) \Rightarrow$ $(5 xx 80) + (5 xx 9) =>$

$400 + 45 \Rightarrow$ $400 + 45 =>$

$445$ $445$